-0.05x^2+44x-1200=0

Solution for -0.05x^2+44x-1200=0 equation:

-0.05x^2+44x-1200=0

a = -0.05; b = 44; c = -1200;
Δ = b2-4ac
Δ = 442-4·(-0.05)·(-1200)
Δ = 1696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1696}=\sqrt{16*106}=\sqrt{16}*\sqrt{106}=4\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{106}}{2*-0.05}=\frac{-44-4\sqrt{106}}{-0.1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{106}}{2*-0.05}=\frac{-44+4\sqrt{106}}{-0.1}
$